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SimpleStrat

NewWebberCash

Poll

Plz Choose which section of NewSitnGo to improve first
13% 13% [ 2 ]
6% 6% [ 1 ]
26% 26% [ 4 ]
33% 33% [ 5 ]
20% 20% [ 3 ]
0% 0% [ 0 ]
0% 0% [ 0 ]

Total Votes : 15

    umm why this section of code?

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    kano

    kano
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    Posts: 81
    Join date: 2009-08-14
    • Post n°1

    umm why this section of code?

    Post by kano on Sun Jan 31, 2010 7:49 am

    When OpponentsAtTable = 1 and BigBlindSize = 100 and StackSize >= 120
    When raises >= 0 RaiseMax force

    When OpponentsAtTable = 1 and BigBlindSize = 120 and StackSize >= 100
    When raises >= 0 RaiseMax force

    When OpponentsAtTable = 1 and BigBlindSize = 160 and StackSize >= 75
    When raises >= 0 RaiseMax force

    When OpponentsAtTable = 1 and BigBlindSize = 200 and StackSize >= 55
    When raises >= 0 RaiseMax force

    When OpponentsAtTable = 1 and BigBlindSize = 240 and StackSize >= 42
    When raises >= 0 RaiseMax force

    When OpponentsAtTable = 1 and BigBlindSize = 300 and StackSize >= 34
    When raises >= 0 RaiseMax force

    When OpponentsAtTable = 1 and BigBlindSize = 400 and StackSize >= 25
    When raises >= 0 RaiseMax force

    When OpponentsAtTable = 1 and BigBlindSize = 500 and StackSize >= 20
    When raises >= 0 RaiseMax force

    When OpponentsAtTable = 1 and BigBlindSize = 600 and StackSize >= 17
    When raises >= 0 RaiseMax force

    When OpponentsAtTable = 1 and BigBlindSize = 800 and StackSize >= 12
    When raises >= 0 RaiseMax force


    that would mean going all in with any two cards BAD PLAY.. widen range .. yes... RAISE MAX EVERYTHING??... no
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    webber04

    webber04



    Posts: 1937
    Join date: 2009-04-30
    Age: 30
    • Post n°2

    Re: umm why this section of code?

    Post by webber04 on Sun Jan 31, 2010 12:47 pm

    it is not a bad play
    read any book on heads up play and it will tell u that when u are a 4 to 1 chip leader the best way to finish off your opponent is to push his small stack with any 2

    I can of course change this, if i notice more 2nds than 1sts
    but i'm about dead even in 2nds and 1sts


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    kano

    kano
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    • Post n°3

    Re: umm why this section of code?

    Post by kano on Sun Jan 31, 2010 3:28 pm

    its just that the last 3 heads up ive seen.. the bot has played predictable and too loose with a great lead is all
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    webber04

    webber04



    Posts: 1937
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    Age: 30
    • Post n°4

    Re: umm why this section of code?

    Post by webber04 on Sun Jan 31, 2010 3:44 pm

    looks like the spreadsheet is pretty much dead even as well


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    webber04

    webber04



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    • Post n°5

    Re: umm why this section of code?

    Post by webber04 on Thu Feb 04, 2010 1:14 am

    just so everyone knows, i am working on the heads up play and should have a new version ready some time tomorrow


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    kano

    kano
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    • Post n°6

    Re: umm why this section of code?

    Post by kano on Thu Feb 04, 2010 1:31 am

    SWEEEEEEEEET!!
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    jj1002

    jj1002
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    Posts: 41
    Join date: 2009-09-08
    • Post n°7

    Re: umm why this section of code?

    Post by jj1002 on Thu Feb 04, 2010 6:48 pm

    webber04 wrote:just so everyone knows, i am working on the heads up play and should have a new version ready some time tomorrow


    Do you think this new heads up code is portable enough to be moved into newsitngo?
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    webber04

    webber04



    Posts: 1937
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    Age: 30
    • Post n°8

    Re: umm why this section of code?

    Post by webber04 on Thu Feb 04, 2010 6:51 pm

    yep
    it is actually working well
    it is more random

    after the last 54 sngos
    ive had 24 ITM's
    12 - 1sts
    5 - 2nds
    7 - 3rds


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    kano

    kano
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    • Post n°9

    Re: umm why this section of code?

    Post by kano on Thu Feb 04, 2010 7:00 pm

    haha im glad you took my advice webber Smile im currently testing out your mtt profile for a few days and ill get back to this one after that
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    webber04

    webber04



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    • Post n°10

    Re: umm why this section of code?

    Post by webber04 on Sun Feb 07, 2010 12:21 am

    ok everyone plz post results in the input form


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